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Answer to Question #74560 in Physics for ABE
Question #74560
a force of 3.9 N acts on a(n)c5.1 kg object for 21.2 s. What is the object
s change in momentum?
s change in momentum?
Expert's answer
If a force F is applied to a particle for a time interval Δt, the momentum of the particle changes by
∆p=F∆t
So
∆p=3.9×21.2=82.7 N∙s
∆p=F∆t
So
∆p=3.9×21.2=82.7 N∙s
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