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Answer to Question #74498 in Physics for Victor
Question #74498
Calculate the velocity of water flowing out of the opening of a tank located at a depth of 5m below the liquid surface
Expert's answer
The Torricelli's law states
v=√2gh
So
v=√(2×10×5)=10 m/s
v=√2gh
So
v=√(2×10×5)=10 m/s
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