Question

A 105 g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track. What is the final sped in meters per second of the toy car if it’s initial speed is 1.8 m/s and it costs up the frictionless slope gaining 0.0705 m in altitude.

Answer 1

Answer on Question #74313-Physics-Other

A 105 g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track. What is the final speed in meters per second of the toy car if it's initial speed is 1.8 m/s and it costs up the frictionless slope gaining 0.0705 m in altitude.

Solution

From the conservation of energy:

$$\frac {m v _ {f} ^ {2}}{2} + m g h = \frac {m v _ {i} ^ {2}}{2}$$ $$v _ {f} = \sqrt {v _ {i} ^ {2} - 2 g h} = \sqrt {1.8 ^ {2} - 2 (9.8) (0.0705)} = 1.4 \frac {m}{s}.$$

Answer: $1.4\frac{m}{s}$.

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