Answer to Question #73584 in Physics for SHAHIN

Question #73584
the interaction energy between two atoms is given by e(r)=(-A/r +B/r7) where r is the inter atomic separation.show that for the particles to be in equilibrium.r=re=(7B/A) and show that for the equilibrium the energy of attraction is
seven times the energy of repulsion
1
Expert's answer
2018-02-20T09:07:08-0500
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