Question #73432

A breeder want to wall off his four-sided plot of flat land. He measures the first three sides, A, B, and C. A=4.75km, B=2.29km, and C=2.9km. What is the length of the vector D in kilometers?

Expert's answer

Answer on Question #73432-Physics-Other

A breeder want to wall off his four-sided plot of flat land. He measures the first three sides, A, B, and C. A=4.75km, B=2.29km, and C=2.9km. What is the length of the vector D in kilometers?

Solution

Dx=−(Ax+Bx+Cx)=−(4.75cos⁡7.5∘−2.29sin⁡16∘−2.9cos⁡19∘)=−1.336kmD _ {x} = - \left(A _ {x} + B _ {x} + C _ {x}\right) = - (4. 7 5 \cos 7. 5 {}^ {\circ} - 2. 2 9 \sin 1 6 {}^ {\circ} - 2. 9 \cos 1 9 {}^ {\circ}) = - 1. 3 3 6 k mDy=−(Ay+By+Cy)=−(−4.75sin⁡7.5∘+2.29cos⁡16∘+2.9sin⁡19∘)=−2.525kmD _ {y} = - \left(A _ {y} + B _ {y} + C _ {y}\right) = - (- 4. 7 5 \sin 7. 5 {}^ {\circ} + 2. 2 9 \cos 1 6 {}^ {\circ} + 2. 9 \sin 1 9 {}^ {\circ}) = - 2. 5 2 5 k m


The length of the vector D is


D=(−1.336)2+(−2.525)2=2.86km.D = \sqrt {(- 1. 3 3 6) ^ {2} + (- 2. 5 2 5) ^ {2}} = 2. 8 6 k m.


Answer: 2.86km2.86\mathrm{km}

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