Answer to Question #72919 in Physics for Richelle Kibbey

Question

Svetich holds a bowling ball on a string 1.6 meters above the ground. She lets it go. At the bottom of the swing, how fast is the bowling ball traveling? Assume the bottom of the swing is just close enough to the floor not to hit the floor and stop.

Answer 1

From the conservation of energy:
(mv^2)/2=mgh
The speed of the bowling ball is
v=√2gh
v=√(2(9.8)(1.6) )=5.6 m/s.