Question

A 40g bullet with a velocity of 500 m/s hits a 3kg wooden block at rest. After impact, the bullet lodges in the wooden block. Find the velocity of the bullet and block after impact

Answer 1

Answer on Question #72866 Physics / Other

A $m = 40$ g bullet with a velocity of $u = 500 \, \text{m/s}$ hits a $M = 3 \, \text{kg}$ wooden block at rest. After impact, the bullet lodges in the wooden block. Find the velocity $v$ of the bullet and block after impact.

Solution:

The law of conservation of momentum gives

$$m u + M 0 = (m + M) v$$

Thus

$$v = \frac{m u}{m + M}$$ $$v = \frac{0.04 \times 500}{0.04 + 3} = 6.6 \, \text{m/s}$$

Answer: $6.6 \, \text{m/s}$

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