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Answer to Question #72817 in Physics for jessie
Question #72817
Find the moment of inertia of a solid cylinder of mass 3.0kg and radius of .50m, which s free to rotate about an axis through its center
Expert's answer
The moment of inertia of a solid cylinder
I=mR^2/2=3×0.5^2/2=0.375 kg×m^2
I=mR^2/2=3×0.5^2/2=0.375 kg×m^2
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