Question #72177

A space ship of mass 50000 kg is traveling at a speed of 11500 m/s in outer space. Except for the force generated by its own engine, no other force acts on the ship. As the engine exerts a constant force of 400000 N, The ship moves a distance0f 2500000 m in the direction of the force of the engine. Determine the final speed of the ship
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Expert's answer

2018-01-03T08:53:07-0500

Answer on Question #72177 Physics / Other

A space ship of mass m=50000kgm = 50000 \, \mathrm{kg} is traveling at a speed of vi=11500m/sv_i = 11500 \, \mathrm{m/s} in outer space. Except for the force generated by its own engine, no other force acts on the ship. As the engine exerts a constant force of F=400000NF = 400000 \, \mathrm{N}, The ship moves a distance of d=2500000md = 2500000 \, \mathrm{m} in the direction of the force of the engine. Determine the final speed of the ship.

Solution:

The distance


d=vf2vi22ad = \frac{v_f^2 - v_i^2}{2a}


So, the final velocity


vf=vi2+2adv_f = \sqrt{v_i^2 + 2ad}


From the Newton's second law


F=maF = ma


we obtain the acceleration


a=Fm.a = \frac{F}{m}.


Finally


vf=vi2+2Fdmvf=115002+2×400000×250000050000=13124m/s\begin{array}{l} v_f = \sqrt{v_i^2 + \frac{2Fd}{m}} \\ v_f = \sqrt{11500^2 + \frac{2 \times 400000 \times 2500000}{50000}} = 13124 \, \mathrm{m/s} \end{array}


Answer: 13124m/s13124 \, \mathrm{m/s}

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