Question

While in a helicopter traveling straight up at 25m/s you accidentally drop your sunglasses when you are 30m above the ground. What is the speed of your sunglasses when they hit the ground?

Answer 1

Distance of sunglasses to the ground
h=(v_final^2-v_initial^2)/2g
So, final velocity
v_final=√(v_initial^2+2gh)=√(25^2+2×9.8×30)=34.8 m⁄s.