Question #71211

Lance Armstrong is accelerating up one of the hills on his bike in The Tour de France. The
combined mass is 80.0 kg. The hill is 650 m long and the total elevation change of the
hill is 25 m. His speed at the bottom of the hill is 2.0 m/s. Lance reaches the top of the
hill in 150 seconds and is traveling at 7.5 m/s. If force of friction on the bike
wheels is 35 N, find the average human power
1

Expert's answer

2017-11-22T15:39:07-0500

Answer on Question #71211-Physics-Other

Lance Armstrong is accelerating up one of the hills on his bike in The Tour de France. The combined mass is 80.0 kg. The hill is 650 m long and the total elevation change of the hill is 25 m. His speed at the bottom of the hill is 2.0 m/s. Lance reaches the top of the hill in 150 seconds and is traveling at 7.5 m/s. If force of friction on the bike wheels is 35 N, find the average human power

Solution

Total work is


W=ΔKE+ΔPE+WfrW = \Delta \mathrm{KE} + \Delta \mathrm{PE} + W_{fr}ΔKE=12m(vf2vl2)=1280(7.5222)=2090J\Delta \mathrm{KE} = \frac{1}{2} m \left(v_{f}^{2} - v_{l}^{2}\right) = \frac{1}{2} 80 \left(7.5^{2} - 2^{2}\right) = 2090 \, JΔPE=809.825=19600J\Delta PE = 80 \cdot 9.8 \cdot 25 = 19600 \, J


Work done by the friction force is


Wfr=Ffrl=35650=22750JW_{fr} = F_{fr} l = 35 \cdot 650 = 22750 \, J


Total work is


W=2090+19600+22750=44440JW = 2090 + 19600 + 22750 = 44440 \, J


Power is


P=44440150=300W.P = \frac{44440}{150} = 300 \, W.


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