Question #70476

A football quarterback shows off his skill by throwing a pass 45.70 m downfield and into a bucket. The quarterback consistently launches the ball at 38.00 ∘ above horizontal, and the bucket is placed at the same level from which the ball is thrown.
What initial speed is needed so that the ball lands in the bucket? I got 21.5 m

By how much would the launch speed have to be increased if the bucket is moved to 48.70 m downfield?
1

Expert's answer

2017-10-11T15:22:07-0400

Answer on Question #70476-Physics-Other

A football quarterback shows off his skill by throwing a pass 45.70 m downfield and into a bucket. The quarterback consistently launches the ball at 38.00 ♦ above horizontal, and the bucket is placed at the same level from which the ball is thrown.

What initial speed is needed so that the ball lands in the bucket? I got 21.5 m

By how much would the launch speed have to be increased if the bucket is moved to 48.70 m downfield?

Solution

Formula for the range of projectile is


x=v02sin2θgx = \frac {v _ {0} ^ {2} \sin 2 \theta}{g}


The initial speed is


v0=gxsin2θ=(9.81)(45.7)sin2(38)=21.5ms.v _ {0} = \sqrt {\frac {g x}{\sin 2 \theta}} = \sqrt {\frac {(9 . 8 1) (4 5 . 7)}{\sin 2 (3 8)}} = 2 1. 5 \frac {m}{s}.


New speed is


v0=gxsin2θ=(9.81)(48.7)sin2(38)=22.2ms.v _ {0} ^ {\prime} = \sqrt {\frac {g x ^ {\prime}}{\sin 2 \theta}} = \sqrt {\frac {(9 . 8 1) (4 8 . 7)}{\sin 2 (3 8)}} = 2 2. 2 \frac {m}{s}.


The increase in speed is


v0v0=22.221.5=0.7ms.v _ {0} ^ {\prime} - v _ {0} = 2 2. 2 - 2 1. 5 = 0. 7 \frac {m}{s}.


Answer provided by https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS