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Answer to Question #70331 in Physics for Tom
Question #70331
A person falls from rest at a height of five meters. Their mass is 70kg. When they land the impact has a duration of 0.1 seconds. What forces was developed on impact
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Person's weight = 70 kg. Velocity initial =0m/s and Velocity final = 5m/0.1s =50m/s. Use acceleration: a=change of V / change of time = 50-0/.1-0 = 500m/s^2. Now Force = mass*a = (70*500)kg*m/s^2 =3500N
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