Answer to Question #70068 in Physics for Manoj

Question #70068

0 The modulus of rigidity of a wire is it a =(2LN)/(Pie×r ^4×thita) The following measurements are made for L, r and thita/ N r = 1.5 ± 0.05 mm L = 400 ± 2 mm thita/ N = 6.00 ± 0.20 rad N-1 m-1 Obtain the best value of its.

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