Question

A child throws a ball vertically upwards and catches the ball 2.00 seconds later.
The acceleration due to gravity, g=-10m/s-2.
so what is the maximum height in metres that the ball reaches if she throws it at 20m/s initial velocity?

Answer 1

Answer on Question #69589-Physics / Other

A child throws a ball vertically upwards and catches the ball $\tau = 2.00$ s later. The acceleration due to gravity, $g = 10 \, \mathrm{m/s}^2$. So what is the maximum height in meters that the ball reaches if she throws it at $u = 20 \, \mathrm{m/s}$ initial velocity?

Solution

Error in task!

For the initial speed of the ball $20\,\mathrm{m/s}$, the time must be $4.00\,\mathrm{s}$.

The maximum height is

$$h_{\max} = ut - \frac{gt^2}{2}, \qquad t = \frac{\tau}{2} = 2.00\,\mathrm{s}.$$ $$h_{\max} = 20 \times 2 - \frac{10 \times 2^2}{2} = 20\,\mathrm{m}.$$

Answer: $h_{\max} = 20\,\mathrm{m}$.

Answer provided by AssignmentExpert.com