Question

A shock absorber acts like an elastic spring of
constant k. It compresses by 2.5 cm when a mass m
is placed on it. When the absorber-mass system is
pressed and left, it begins to oscillate. Calculate the
frequency of oscillations. Take g : 10 ms-2

Answer 1

Answer on Question #69287-Physics-Other

A shock absorber acts like an elastic spring of constant k. It compresses by 2.5 cm when a mass m is placed on it. When the absorber-mass system is pressed and left, it begins to oscillate. Calculate the frequency of oscillations. Take g: 10 ms-2

Solution

$$kx = mg$$ $$k = \frac{mg}{x}$$

The angular frequency of oscillations is

$$\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{mg}{mx}} = \sqrt{\frac{g}{x}} = \sqrt{\frac{10}{0.025}} = 20 \frac{rad}{s}.$$

Answer: $20 \frac{rad}{s}$.

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