Answer on Question #69193- Physics / Other
A particle moves along the curve y=Ax3 such that x=Bt, and A and B are constant. Express the position vector of the particle in the form r(t)=xi+yj. Calculate the velocity of the particle along this path at any instant.
Solution:
x(t)=Bt,y(t)=Ax3=AB3t3.
The position vector of the particle
r(t)=x(t)i+y(t)j=Bti+AB3t3j.
The velocity of the particle
v(t)=r′(t)=x′(t)i+y′(t)j=Bi+3AB3t2j.
**Answer**: v(t)=Bi+3AB3t2j
Answer provided by https://www.AssignmentExpert.com
Comments