Question #69193

A particle moves along the curve y=ax^3 such
that x=Bt, and A and B are constant,
Express the position vector of the particle in the lorm r(t) = xi^+ yj.^ Calculate the velocity
of the particle along this path at any instant.
1

Expert's answer

2017-07-11T14:33:06-0400

Answer on Question #69193- Physics / Other

A particle moves along the curve y=Ax3y = Ax^3 such that x=Btx = Bt, and AA and BB are constant. Express the position vector of the particle in the form r(t)=xi+yj\mathbf{r}(t) = x\mathbf{i} + y\mathbf{j}. Calculate the velocity of the particle along this path at any instant.

Solution:

x(t)=Bt,x(t) = Bt,y(t)=Ax3=AB3t3.y(t) = Ax^3 = AB^3 t^3.


The position vector of the particle


r(t)=x(t)i+y(t)j=Bti+AB3t3j.\mathbf{r}(t) = x(t)\mathbf{i} + y(t)\mathbf{j} = Bt\mathbf{i} + AB^3 t^3\mathbf{j}.


The velocity of the particle


v(t)=r(t)=x(t)i+y(t)j=Bi+3AB3t2j.\mathbf{v}(t) = \mathbf{r}'(t) = x'(t)\mathbf{i} + y'(t)\mathbf{j} = B\mathbf{i} + 3AB^3 t^2\mathbf{j}.


**Answer**: v(t)=Bi+3AB3t2j\mathbf{v}(t) = B\mathbf{i} + 3AB^3 t^2\mathbf{j}

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