a ideal mixture of C2H6 and C2H4 covered 28 leter volume at 0 degree centigrate and 1 atm .mixture react with 128 gram of oxygen gass and make CO2 and H2O.what is the mole fraction of C2H6?
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Expert's answer
2017-06-21T09:51:06-0400
PV = nRT n=PV/RT=((101 325)(0.028))/((8.31)(273.15))=1.25 mol Let mole of C_2 H_6 and C_2 H_4 is a and b respectively. Therefore, a + b = 1.25→b= 1.25-a Now, C_2 H_6+7/2 O_2→2CO_2+3H_2 O C_2 H_4+3O_2→2CO_2+2H_2 O Thus, number of moles of O_2 needed for complete reaction of mixture is n(O_2 )=7a/2+ 3b. n(O_2 )=m(O_2 )/M(O_2 ) =128/32 7a/2+ 3b=128/32 Thus, 7a/2+ 3(1.25-a)=128/32 a=0.5 mol Therefore, mole fraction of C_2 H_6 is 0.5/1.25=0.4.
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