Answer to Question #61565 in Physics for Sakura

Question

The isotope 35Cl has a mass of 5.80X10^-26kg and a negative charge of 1.60X10^-19C. It is accelerated, and passes through a velocity selector where the electric field is 5.85X10^4V/m, and the magnetic field is 0.275T. The ion is deflected by magnetic field of 2.00T.
a)What is the radius of curvature of this ion?
b)If a heavier isotope of chlorine is used but one with the same charge, would the radius of curvature be large or smaller? Ex[lain your reasoning by referring to the equation you used to determine the mass.