Question

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.1 m long, and the nerve impulse speed is 18 m/s, how long does it take for the nerve signal to travel this distance?

Answer 1

Answer on Question #58752, Physics / Other |

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.1 m long, and the nerve impulse speed is 18 m/s, how long does it take for the nerve signal to travel this distance?

Solution:

The time is

$$\text{Time} = \frac{\text{Distance}}{\text{Speed}}$$ $$t = \frac{d}{v} = \frac{1.1\ \text{m}}{18\ \text{m/s}} = 0.061\ \text{s}$$

Answer. 0.061 s

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