Question #57063

If there were a speed limit for this train as
it traveled through a city, but not a weight
limit, what mass must be added to the train
to slow it down to 5 m/s while at the same
time keeping the momentum the same as in
the second part?
Answer in units of kg.
1

Expert's answer

2015-12-22T04:58:51-0500

Answer on Question #57063, Physics / Other

If there were a speed limit for this train as it traveled through a city, but not a weight limit, what mass must be added to the train to slow it down to 5m/s5\mathrm{m/s} while at the same time keeping the momentum the same as in the second part?

Answer in units of kg.

Solution:

Momentum is defined to be the mass of an object multiplied by the velocity of the object.


p=mvp = m v


The conservation of momentum states that, within some problem domain, the amount of momentum remains constant.

Thus,


p1=p2p _ {1} = p _ {2}mv1=(m+mx)v2m v _ {1} = (m + m _ {x}) v _ {2}mv1=mv2+mxv2m v _ {1} = m v _ {2} + m _ {x} v _ {2}mxv2=m(v1v2)m _ {x} v _ {2} = m \left(v _ {1} - v _ {2}\right)mx=m(v1v2)v2m _ {x} = \frac {m (v _ {1} - v _ {2})}{v _ {2}}


where v2=5m/sv_{2} = 5 \, \text{m/s},

m=m = initial mass of train,

v1=v_{1} = velocity of train from the second part of question.

Answer: mx=m(v1v2)v2m_{x} = \frac{m(v_{1} - v_{2})}{v_{2}}.


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