Answer on Question #52298, Physics, Other
7. An 80-kg man and his car are suddenly accelerated from rest to a speed of 5m/s as a result of a rear-end collision. Assuming the time taken to be 0.3s, find:
a) the impulse on the man and
b) the average force exerted on him by the back seat of his car.
Solution:
The impulse on the man is
p=mv=80∗5=400kg⋅m/s
If a force F is applied to a particle for a time interval t, the momentum of the particle changes by an amount
p=Ft
Thus,
F=tp=0.3400=1333.3N
**Answer:** a) 400kg⋅m/s; b) 1333.3N
8. An airplane propeller is rotating at 1900 rev/min.
a. Compute the propeller's angular velocity in rad/s.
b. How long in seconds does it take for the propeller to turn through 30.0 degrees?
Solution:
a. The conversion between a frequency f measured in hertz and an angular velocity ω measured in radians per second are:
ω=2πf
We have f=1900rev/min=1900/60=395Hz
ω=2πf=2⋅3.14159⋅95/3=199rad/s
b. The angle is
φ=ωt
Thus,
t=ωφ=180∘30∘∗π∗1991=0.0026s
**Answer:** a. 199 rad/s; b. 0.0026 s.
9. A disk with a 1.0-m radius reaches a maximum angular speed of 18 rad/s before it stops 30 revolutions after attaining the maximum speed. How long did it take the disk to stop?
Solution:
distance traveled=circumference∗number of revolutions
Thus,
d=2πR∗30=60π m
The linear speed is
v=Rω=1∗18=18 m/s
The time is
t=vd=1860π=10.5 s
Answer: 10.5 s.
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