Question #52298

7. An 80-kg man and his car are suddenly accelerated from rest to a speed of 5 m/s
as a result of a rear-end collision. Assuming the time taken to be 0.3s, find:
a) the impulse on the man and
b) the average force exerted on him by the back seat of his car.
8. An airplane propeller is rotating at 1900 rev/min.
a. Compute the propeller's angular velocity in rad/s.
b. How long in seconds does it take for the propeller to turn through 30.0
degrees?
9. A disk with a 1.0-m radius reaches a maximum angular speed of 18 rad/s before
it stops 30 revolutions after attaining the maximum speed. How long did it take
the disk to stop?
1

Expert's answer

2015-04-30T02:29:31-0400

Answer on Question #52298, Physics, Other

7. An 80-kg man and his car are suddenly accelerated from rest to a speed of 5m/s5\mathrm{m/s} as a result of a rear-end collision. Assuming the time taken to be 0.3s, find:

a) the impulse on the man and

b) the average force exerted on him by the back seat of his car.

Solution:

The impulse on the man is


p=mv=805=400kgm/sp = m v = 80 * 5 = 400 \mathrm{kg} \cdot \mathrm{m/s}


If a force FF is applied to a particle for a time interval tt, the momentum of the particle changes by an amount


p=Ftp = F t


Thus,


F=pt=4000.3=1333.3NF = \frac{p}{t} = \frac{400}{0.3} = 1333.3 \mathrm{N}


**Answer:** a) 400kgm/s400\mathrm{kg}\cdot \mathrm{m/s}; b) 1333.3N1333.3\mathrm{N}

8. An airplane propeller is rotating at 1900 rev/min.

a. Compute the propeller's angular velocity in rad/s.

b. How long in seconds does it take for the propeller to turn through 30.0 degrees?

Solution:

a. The conversion between a frequency f measured in hertz and an angular velocity ω\omega measured in radians per second are:


ω=2πf\omega = 2 \pi f


We have f=1900rev/min=1900/60=953Hzf = 1900 \, \text{rev/min} = 1900 / 60 = \frac{95}{3} \, \text{Hz}

ω=2πf=23.1415995/3=199rad/s\omega = 2 \pi f = 2 \cdot 3.14159 \cdot 95 / 3 = 199 \, \text{rad/s}


b. The angle is


φ=ωt\varphi = \omega t


Thus,


t=φω=30π1801199=0.0026st = \frac{\varphi}{\omega} = \frac{30{}^{\circ} * \pi}{180{}^{\circ}} * \frac{1}{199} = 0.0026 \, \text{s}


**Answer:** a. 199 rad/s; b. 0.0026 s.

9. A disk with a 1.0-m radius reaches a maximum angular speed of 18 rad/s before it stops 30 revolutions after attaining the maximum speed. How long did it take the disk to stop?

Solution:


distance traveled=circumferencenumber of revolutionsdistance \ traveled = circumference * number \ of \ revolutions


Thus,


d=2πR30=60π md = 2\pi R * 30 = 60\pi \ m


The linear speed is


v=Rω=118=18 m/sv = R\omega = 1 * 18 = 18 \ \mathrm{m/s}


The time is


t=dv=60π18=10.5 st = \frac{d}{v} = \frac{60\pi}{18} = 10.5 \ \mathrm{s}


Answer: 10.5 s.

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