Question #350949

5 m wire made of gold ( ρgold = 2.4 x 10−8 ) has a cross-sectional area of 2 mm.

Calculate the voltage if a 32 A current runs through the wire.

Expert's answer

The Ohm's law says

"I=\\frac{V}{R}"Hence, the voltage

"V=IR=I\\rho\\frac{l}{A}""V=32*2.4*10^{-8}*\\frac{5}{3.14*0.001^2}=1.2\\:\\rm V"

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