Question

A closed container of cubic shape is 15 cm on a side contains four times Avogadro's number of molecules at a temperature of 20.0 degree celsius.Calculate the amount of force exerted by the gas on one of the walls of the vessel.

Answer 1

Given:

$a=0.15\:\rm m$

$N=4N_A$

$T=t+273=293\:\rm K$

$$F=pA=\frac{N}{N_A}\frac{RT}{V}A$$

$$F=\frac{N}{N_A}\frac{RT}{a^3}a^2=\frac{N}{N_A}\frac{RT}{a}$$

$$F=4*\frac{8.31*293}{0.15}=6.49*10^4\:\rm N$$