Answer to Question #349938 in Physics for Professor Proton

Question #349938

From 12 m/s to 54 km/hr , a 1500 kg jeepney accelerates that produce a force of 450 N. Find

a) the momentum of the jeepney.

b) the time to accelerate ?


1
Expert's answer
2022-06-13T08:24:00-0400

Given:

vi=12m/sv_i=12\:\rm m/s

vf=54km/h=15m/sv_f=54\:\rm km/h=15\:\rm m/s

m=1500kgm=1500\:\rm kg

F=450NF=450\:\rm N


(a)

pi=mvi=150012=18000kgm/sp_i=mv_i=1500*12=18000\:\rm kg\cdot m/s

pf=mvf=150015=22500kgm/sp_f=mv_f=1500*15=22500\:\rm kg\cdot m/s

(b)

F=ΔpΔtF=\frac{\Delta p}{\Delta t}

Δt=ΔpF=2250018000450=10s\Delta t=\frac{\Delta p}{F}=\frac{22500-18000}{450}=10\:\rm s


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