Question #349614

Two charges (βˆ’12.6 Γ— 10βˆ’12 𝐢𝐢 and βˆ’ 1.13 Γ— 10βˆ’13 𝐢𝐢) are separated by a distance of



3.75 πœ‡πœ‡π‘šπ‘š. Compute the force of attraction between them.

1
Expert's answer
2022-06-10T08:28:39-0400
F=kq1q2r2F=k\frac{q_1q_2}{r^2}

F=9βˆ—109Nβ‹…m2C2βˆ—12.6βˆ—10βˆ’12β€…Cβˆ—1.13βˆ—10βˆ’13β€…C(3.75βˆ—10βˆ’6β€…m)2=9.11βˆ—10βˆ’4β€…NF=9*10^9\frac{\rm N\cdot m^2}{\rm C^2}*\frac{12.6*10^{-12}\: \rm C*1.13*10^{-13}\: C}{(3.75*10^{-6}\:\rm m)^2}\\ =9.11*10^{-4}\:\rm N


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