Question

What is the horizontal force needed to accelerate a 42 grocery cart from rest to a velocity of 0.80 m/s in 1.75s

Answer 1

Given:

$m=42\:\rm kg$

$v_1=0\:\rm m/s$

$v_2=0.80\:\rm m/s$

$t=1.75\:\rm s$

$$F=ma=m\frac{v_2-v_1}{t}$$

$$F=42*\frac{0.80-0}{1.75}=19.2\:\rm N$$