Question

A 3000-lb. car has an engine which can deliver 80 hp to the rear wheels. What is the maximum velocity at which the car can climb a 15 degree hill?

Answer 1

Given:

$3000\:\rm lb=13344\:N$

$80\:\rm hp=58840\: W$

$$P=Fv\cos\theta$$

$$v=\frac{P}{F\cos\theta}=\frac{58840}{13344*\cos 15^\circ}=4.6\:\rm m/s$$