Answer to Question #348228 in Physics for Umme

Question #348228

Find the velocity aquired by an electron in falling through a potential difference of 2000 volts.

Expert's answer

"\\frac{mv^2}{2}=eV"

"v=\\sqrt{\\frac{2eV}{m}}=\\sqrt{\\frac{2*1.6*10^{-19}*2000}{9.1*10^{-31}}}=2.65*10^7\\:\\rm m\/s"

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