Answer to Question #347129 in Physics for Elora

Question #347129

A baseball leaves the bat at an angle of 37° above the horizontal at a speed of 120 ft/s. How high does it go? How far forward is it at its highest point?

1
Expert's answer
2022-06-01T12:49:07-0400
hmax=(v0sinθ)22g=(120sin37)2232.17=81fth_{\max}=\frac{(v_0\sin\theta)^2}{2g}=\frac{(120\sin37^\circ)^2}{2*32.17}=81\:\rm ft

L=v02sin2θ2g=1202sin74232.17=215ftL=\frac{v_0^2\sin2\theta}{2g}=\frac{120^2\sin74^\circ}{2*32.17}=215\:\rm ft


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