Question

A block of mass 30.0 [kg] slides down from the top of the incline. The coefficient of kinetic friction between the block and the incline is 𝜇𝑘 = 0.350. What is the total work done on the block as it reaches the bottom of the incline?

Answer 1

$$W=mgh-F_f d=mgd\sin\theta-\mu mg d\cos\theta\\ =mgd(\sin\theta-\mu\cos\theta)$$