Answer to Question #346628 in Physics for Jerry

Question #346628

A power station conveyor lifts 500 tons of coal per hour to a height of 80 feet. What average

horsepower is required?

Expert's answer

"P=\\frac{W}{t}=\\frac{mgh}{t}""={\\rm\\frac{500*10^3\\: kg*9.8\\: N\/kg*80*0.305\\: m}{3600\\: s}}"

"=3.32*10^4\\:\\rm W=44.5\\: hp"

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