Question

VI. Find the maximum speed of a particle that undergoes SHM with a period of 

             0.50 s and an amplitude of 20 mm. 

 

    

Answer 1

$$v_{\max}=A\omega=A*\frac{2\pi}{T}\\ =20\:\rm mm*\frac{2\pi}{0.50\:\rm s}=250\:\rm mm/s=0.25\: m/s$$