Question #345879

Consider cobalt-60 (⁶⁰CO) with a half-line of 5.25 years. How many years will it take for its activity to decrease to one-fourth of its original amount?

1
Expert's answer
2022-05-30T15:18:17-0400
A=A02t/t1/2A=A_0*2^{-t/t_{1/2}}

14A0=A02t/t1/2\frac{1}{4}A_0=A_0*2^{-t/t_{1/2}}

t=2t1/2=25.25yr=10.5yrt=2t_{1/2}=2*5.25\:\rm yr=10.5\:yr


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