Answer to Question #345497 in Physics for yusei

Question #345497

An object is projected from the ground with an initial velocity of 20.25 m/s at 50degrees above the horizontal. Find the following. (Show your complete solution.)                               a. Horizontal and vertical components of its initial velocity              b.. Time to reach the maximum height                          c. Range


1
Expert's answer
2022-05-28T08:23:04-0400

Given:

v0=20.25m/sv_0=20.25\:\rm m/s

θ=50\theta=50^\circ

(a)

v0x=v0cosθ=20.25cos50=13.0m/sv_{0x}=v_0\cos\theta=20.25*\cos50^\circ=13.0\:\rm m/s

v0y=v0sinθ=20.25sin50=15.5m/sv_{0y}=v_0\sin\theta=20.25*\sin50^\circ=15.5\:\rm m/s

(b)

t1=v0yg=15.59.8=1.58st_1=\frac{v_{0y}}{g}=\frac{15.5}{9.8}=1.58\rm\: s

(c)

R=v0x2t1=13.021.58=41.2  mR=v_{0x}*2t_1\\ =13.0*2*1.58=41.2\;\rm m


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