Question #345466

sec/ohm is equal to


Expert's answer

sΩ=skgm2s3A2=s4A2kgm2\rm\frac{s}{\Omega}=\frac{s}{\frac{kg\cdot m^2}{s^3\cdot A^2}}=\frac{s^4\cdot A^2}{kg\cdot m^2}

sΩ=ss/F=F\rm\frac{s}{\Omega}=\frac{s}{s/F}=F


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