Answer to Question #345438 in Physics for Arem

Question

a ball was pushed by a force of 17.27 newton going to east. and travels a certain distance of 0.05678 kilometer in 0.033 minute. find the ball's momentum

Answer 1

$$d=v_0t+at^2/2,\quad v_0=0$$

$$a=2d/t^2=2*(56.78\rm\: m)/(1.98\:\rm s)^2=28.97\:\rm m/s^2$$

$$v_f=v_0+at=0+28.97*1.98=57.35\:\rm m/s$$

$$m=\frac{F}{a}=\frac{17.27\:\rm N}{28.97\:\rm m/s^2}=0.5961\:\rm kg$$

The final momentum of the ball

$$p_f=mv_f\\ =0.5961\:\rm kg\times 57.35\: m/s=34.19\: kg\cdot m/s$$