Answer to Question #344170 in Physics for tom

Question #344170

How much energy is in the elastic potential energy store of a spring with a spring constant of 4 N/m if it is stretched from 1 m to 1.1 m in length?

Expert's answer

"W=\\frac{kx_2^2}{2}-\\frac{kx_1^2}{2}\\\\\n=\\frac{4}{2}*(1.1^2-1.0^2)=0.42\\:\\rm J"

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