Answer to Question #343714 in Physics for romeo

Question #343714

A force 0f 100 N is directed north on a -20 µC point charge. What is the magnitude and direction of the electric field at this point?

Expert's answer

F=qE

E=\frac{F}{q}=\frac{100\:\rm N}{20*10^{-6}\:\rm N/C}=5*10^6\:\rm N

The direction of the electric field at this point is toward south.

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