Question #343198

A 189.3-kg and a 258.9-kg cart approach each other on a horizontal air track. They collide and stick together. After the collision their total kinetic energy is 1142.5 J. What is the speed after the collision

1
Expert's answer
2022-05-20T13:19:45-0400
Ek=mv22E_k=\frac{mv^2}{2}v=2Ek/m=21142.5/(189.3+258.9)=2.258m/sv=\sqrt{2E_k/m}\\ =\sqrt{2*1142.5/(189.3+258.9)}=2.258\:\rm m/s

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