Question #343105

If the work required to speed a car from 10 km/h to 20 km/h is 5.0 x 10^3 J, what would be the work required to increase its speed from 20 km/h to 30 km/h.



1
Expert's answer
2022-05-20T04:53:12-0400
W12=m2(v22v12)W_{12}=\frac{m}{2}(v_2^2-v_1^2)W34=m2(v42v32)W_{34}=\frac{m}{2}(v_4^2-v_3^2)W34=W12v42v32v22v12W_{34}=W_{12}\frac{v_4^2-v_3^2}{v_2^2-v_1^2}W34=5.0103302202202102=8.3103JW_{34}=5.0*10^3*\frac{30^2-20^2}{20^2-10^2}=8.3*10^3\:\rm J

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