Question #342748

Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 63.0-kg man if the man is standing at sea level, a distance of 6.38 x 106 m from earth's center.


1
Expert's answer
2022-05-20T04:53:44-0400
F=Gm1m2r2F=G\frac{m_1m_2}{r^2}

F=6.6710115.98102463.0(6.38106)2=617NF=6.67*10^{-11}*\frac{5.98*10^{24}*63.0}{(6.38*10^6)^2}=617\:\rm N


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