Answer to Question #342710 in Physics for Ma. daniella gapa

Question #342710

When positioned at 90° to a magnetic field, a wire of length 1 m carrying a current of 4 A experiences a force of 0.2 N. What is the strength of the magnetic field?

Expert's answer

F=BIl\sin\theta

B=\frac{F}{Il\sin\theta}=\frac{0.2}{4*1*\sin90^\circ}=0.05\:\rm T

Learn more about our help with Assignments: Physics

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. An electric field with a strength of 1.25x104N/C exerted 2.50 N on a certain test charge, q. Determi
2. 1. A package is dropped from a helicopter flying at a height of 7.5 m while traveling 15 m/s. how fa
3. A kicked football leaves the ground at an angle θ = 45o with the horizontal has an initial speed
4. A package is dropped from a helicopter flying at a height of 7.5 m while traveling 15 m/s. how far d
5. A ball m= 0.14 kg with initial velocity of 40 m/s is hit. it leaves the bat with a velocity of 60 m/
6. A particle with a charge of 4μC is moving at 3 X 106 m/s perpendicularly through a magnetic field w
7. A. An infinitely long wire carries a current of 3A determine the magnitude of the magnetic field 1.