Question #342702

A kicked football leaves the ground at an angle θ = 45o with the horizontal has an initial speed of 25 m/s. Determine the distance of X. Acceleration due to gravity is 9.8 m/s2.



Expert's answer

R=v02sin⁡2θg=252sin⁡90∘9.8=64 mR=\frac{v_0^2\sin2\theta}{g}=\frac{25^2\sin90^\circ}{9.8}=64\:\rm m


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