Question

A ball m= 0.14 kg with initial velocity of 40 m/s is hit. it leaves the bat with a velocity of 60 m/s after 0.001 s. what is the impulse an average net force applied to the ball by the bat.

Answer 1

The impulse

$$\Delta p=m\Delta v=0.14*(60-40)=2.8\:\rm kg\cdot m/s$$

The average force

$$F=\frac{\Delta p}{\Delta t}=\frac{2.8}{0.001}=2800\:\rm N$$