Answer to Question #342670 in Physics for sem

Question

Car B of mass 800kg is moving at a speed of and collides with car A which is stationary

After the collision both cars travel in the same direction as the initial direction of car B

After the collision car A moves at 1.3m/s

A) what is of car B after the collision

B) Calculate the impulse extended on car B by car A

C) State the impulse extended on car A by car B

Answer 1

The law of conservation of momentum says

$$m_Bv_B=m_Bv_B'+m_Av_A'$$

a)

$$v_B'=v_B-(m_A/m_B)v_A'$$

b)

$$\Delta p_{AB}=m_B(v_B'-v_B)=-m_Av_A'$$

c)

$$\Delta p_{BA}=-\Delta p_{AB}$$