Answer to Question #342490 in Physics for cedrick

Question #342490

A box is pulled across a level floor a distance of 0.1 km. Given that 2.0 kJ of work was done in overcoming friction, what was the average friction force?

Expert's answer

"W=Fd\\cos\\theta"

"F=\\frac{W}{d}=\\frac{2000\\: \\rm J}{100\\: \\rm m}=20\\:\\rm N"

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