Answer to Question #342378 in Physics for Ella

Question #342378

An electronic field with a strength of 1.25×10⁴N/C exerted 2.50 Nnon a certain test charges, q. determine charge on q.

Expert's answer

"F=qE"

"q=\\frac{F}{E}=\\frac{2.50}{1.25*10^{4}}=2.0*10^{-4}\\:\\rm C"

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