An arrow moving at 10 m/s is stopped by a target. If the arrow has a mass of 250 g and penetrates 4 cm into the target, what is the force exerted by the arrow on the target?
The energy-work theorem says
"\\frac{mv^2}{2}=Fd""F=\\frac{mv^2}{2d}=\\frac{0.250*10^2}{2*0.04}=313\\:\\rm N"
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