Question #342061

What is the radius of the nucleus of 28/14 Si ? What is its volume?



1
Expert's answer
2022-05-17T16:04:56-0400
R=(1.3fm)A1/3=(1.3fm)281/3=3.95fmR={(1.3\:\rm fm)}\:A^{1/3}\\ =(1.3\:\rm fm)\:28^{1/3}=3.95\:\rm fm

V=43πR3=433.14(3.95fm)3=258fm3V=\frac{4}{3}\pi R^3\\ =\frac{4}{3}*3.14*(\rm 3.95\: fm)^3=258\: fm^3


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